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bugtraq logo Bugtraq mailing list archives

Re: Possible windows+python bug
From: azurIt <azurit () pobox sk>
Date: Tue, 22 Mar 2005 23:05:51 +0100



On Tue, Mar 22, 2005 at 12:21:18PM -0000, liquid () cyberspace org 
wrote:
Start Python and type (of course x.x.x.x should be replaced with
IP address):

import socket
s=socket.socket(socket.AF_INET,socket.SOCK_RAW,4)
s.sendto("",("x.x.x.x",0))

Press ENTER and your win box should crash immediately.

I tested this on WinXP SP2 with Python 2.4.  The result is an
exception:

  socket.error: (10022, 'Invalid argument')

I don't have Python 2.3 installed otherwise I would test that too.

  Neil



i got the same exception, WinXP SP2, Python 2.3.4 .

azurIt

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