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Re: AT&T UVERSE Native IPv6, a HOWTO
From: Eric Oosting <eric.oosting () gmail com>
Date: Tue, 3 Dec 2013 00:04:29 -0500

On Mon, Dec 2, 2013 at 11:11 PM, Rob Seastrom <rs () seastrom com> wrote:


"Ricky Beam" <jfbeam () gmail com> writes:

On Fri, 29 Nov 2013 08:39:59 -0500, Rob Seastrom <rs () seastrom com>
wrote:
So there really is no excuse on AT&T's part for the /60s on uverse
6rd...
...
Handing out /56's like Pez is just wasting address space -- someone
*is*  paying for that space. Yes, it's waste; giving everyone 256
networks when  they're only ever likely to use one or two (or maybe
four), is  intentionally wasting space you could've assigned to
someone else. (or  **sold** to someone else :-)) IPv6 may be huge to
the power of huge, but  it's still finite. People like you are
repeating the same mistakes from  the early days of IPv4...

There's finite, and then there's finite.  Please complete the
following math assignment so as to calibrate your perceptions before
leveling further allegations of profligate waste.


I know this is rhetorical, but my hobby is answering peoples rhetorical
questions.



   Suppose that every mobile phone on the face of the planet was an "end
   site" in the classic sense and got a /48 (because miraculously,
   the mobile providers aren't being stingy).


Very well, I'll play your silly game.

48 bits remaining.



   Now give such a phone to every human on the face of the earth.


33 bits should do it. That gets us to nearly 9 billion people.

15 bits remaining.


   Unfortunately for our conservation efforts, every person with a
   cell phone is actually the cousin of either Avi Freedman or Vijay
   Gill, and consequently actually has FIVE cell phones on active
   plans at any given time.


5 is inconvenient. Lets give everyone 8 mobil phones, using 3 bits.

12 bits remaining.



   Assume 2:1 overprovisioning of address space because per Cameron
   Byrne's comments on ARIN 2013-2, the cellular equipment providers
   can't seem to figure out how to have N+1 or N+2 redundancy rather
   than 2N redundancy on Home Agent hardware.


1 bit for that.

11 bits remaining.

Now we're assigning space out of 2000::/3 for now ... lets keep the other
7/8ths of the ipv6 address block in reserve, using another 3 bits ...
leaving ... carry the one ... 8 bits.



What percentage of the total available IPv6 space have we burned
through in this scenario?  Show your work.


If we give every man, woman, and child on the face of the earth the
equivalent to (16) /48s each, we'll will have used 1/256th of the first
1/8th of the IPv6 address space.

Wolfram says there have been 110 billion homo sapiens that have ever lived.
We need to give every person who has literally ever lived on planet earth
their own /40 before we've used up 2000::/3, and need to move on to the
remaining 87.5% of the address space. (this is where someone will ding me
for the misuse of "literally" somehow with a pointer to theoatmeal comic,
right)

-e



-r





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