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Re: Random number prediction
From: Aaron Horst <anthrax101 () gmail com>
Date: Thu, 30 Jun 2005 11:05:15 -0400
This is an interesting method of reducing the keyspace of attack, but
rand() is still a linear congruent PRNG. It should never be used where
cryptographically secure pseudo-random numbers are needed. I would
suggest using Blum Blum Shub or some method based on an existing
cipher in counter mode.
AnthraX101
On 6/30/05, Gabriele Avosani <avosani.gabriele () libero it> wrote:
Hello there folks,
take a look at this source, its called sidis.c
/*****************************************************************************************************/
/* Sidis
*/
/* CRT rand() function random number predictor
*/
/*
*/
/* works with every windows and unix random generator
*/
/*
*/
/* this is a full service random number predictor
*/
/* the function of CRT rand is the following
*/
/* int rand (void)
*/
/* {
*/
/* _ptiddata ptd = _getptd();
*/
/* return( ((ptd->_holdrand = ptd->_holdrand * 214013L + 2531011L) >>
16) & 0x7fff ); */
/* }
*/
/* As you can see the seed starts to set the variable that is returned from
the pointer */
/* then we have a little mathematic and we get 15 bits
*/
/* ......
*/
/* but, from what i discovered, you can read the explaination in sci.math, i
have made a post there, */
/* we can do this operation
*/
/* x1 = (seed * y + z)
*/
/* x2 = (x1 * y + z)
*/
/* x3 = (x2 * y + z)
*/
/* the random numbers are: x1 >> 15, x2 >> 15, x3 >> 15
*/
/* now .... if we apply a little phormula, i can assure you that:
*/
/* (x2 >> 15 - z >> 15) * y >> 15 gives us x1 >> 15
*/
/* now we can easily brute force the remaining 17 bits
*/
/*
*/
/* Zuc
*/
/*
*/
/*****************************************************************************************************/
#include <stdlib.h>
#include <stdio.h>
#define rand1 666
#define rand2 32767
unsigned long next=-1,w;
void main(void)
{
unsigned long x = (((rand2 >> 15) - (2531011 >> 15) >> 15) * 214013 >> 15)
15;
for(long y=0;y<2^17;y++)
{
w = y * 2^17 + x;
next = (w * 214013 + 2531011) >> 32;
if( (( next * 214013 + 2531011)>> 15 ) == rand1 )break;
}
if(next==-1)
{
printf("Sorry, number not found.\n");
return;
}
for(unsigned short i=0;i<10;i++)
{
printf("Next number n.%i ---
%i\n",i,(next*214013+2531011)>>15);
next=next*214013+2531011;
}
printf("Sic transit gloria mundi.\n");
}
Zuc
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