Re: GET x HTTP/1.0

["Ross Oldbury" <Ross.OLDBURY () gemplus com>]

The Second IP address is an employee of China Telecom who thinks he's a bit
of a hacker.
He tried to attack my firewall on Jun 11 & 14 without success.

Packet log: input DENY eth0 PROTO=6 202.99.64.113:33408 x.x.x.x:111 "trying
to get my RPC info or overflow bug"
I would block both the class B address ranges as they are not to be trusted.

Regards,
Ross
----- Original Message -----
From: "Greg Owen" <gowen () swynwyr com>
To: <incidents () securityfocus com>
Sent: Tuesday, July 24, 2001 2:19 AM
Subject: GET x HTTP/1.0


>     Two of these showed up in my web server logs today:
>
> 202.100.68.22 - - [23/Jul/2001:11:58:37 -0400] "GET x HTTP/1.0" 400 328
> 202.99.64.113 - - [23/Jul/2001:17:23:44 -0400] "GET x HTTP/1.0" 400 328
>
> inetnum              202.100.68.0 - 202.100.68.255
> netname              FEITIAN-INTERNET-COMPANY
> descr                Feitian Internet Company
> descr                Lanzhou,Gansu
> descr                China
> country              CN
>
> inetnum              202.99.64.0 - 202.99.127.255
> netname              CHINANET-TJ
> descr                CHINANET Tianjin province network
> descr                Data Communication Division
> descr                China Telecom
> country              CN
>
>     A quick google search showed one other person wondering what it was
and
> commenting they mostly seemed to be china, and a bunch of server logs that
> showed the same hit.
>
>     Anybody know what this is?  The source makes me wonder.
>
> --
>         gowen -- Greg Owen -- gowen () swynwyr com
>         79A7 4063 96B6 9974 86CA  3BEF 521C 860F 5A93 D66D
>
>
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