Request for urgent help.

[mark antony <mark_p004 () yahoo com au>]

Respected sir

I am am new to use this snort. I have no idea how to use this. I need some information regarding this question. If i 
dont do this i am gonna fail the subject. The university did not provided any guidence on how to use the snort. I dont 
know anything. Please some one help me out.
  You are a security specialist working for ABC Incorporated.  ABC use SNORT as their NIDS which protects their IP 
sub-network being in the range of 203.40.27.128 – 203.40.27.255.  
   
  (a)                                                                                                          A recent 
security vulnerability has been found in OpenSSH.  A junior staff member within the security team developed a new SNORT 
rule to detect this attack.  Your supervisor has asked you to check the work of the junior staff member to ensure there 
are no errors in the SNORT rule.  
  The security vulnerability is described as follows:
  A buffer overflow has been detected in the OpenSSH server.  Exploits have been released and exhibit the following 
characteristics:
  ·         A payload positioned 100 bytes from the start of the data with a string message “You are mine” 
  ·         After the above payload, there is a variable field of 4 bytes specifying a return address.  These 4 bytes 
can be any value.  
  ·         Following the variable 4 bytes return address is the exploit code signature given in HEX as AB 8F 23 8A BC 
92
   
  The rule should:
  ·         when triggered, drop and then log the packet only.
  ·         detect attacks from inside and outside their private network.
  ·         include a message with the log entry as “OpenSSH exploit attempt”.
  ·         include a reference to the CVE number CAN-2006-06-3318
  ·         Have a classification of attempted-admin
   
  The rule written by the junior staff member is as follows:
   
  alert udp !203.40.27.0/24 any -> 203.40.27.128/24 23 (msg: “OpenSSH exploit attempt”; cve:CAN-2006-06-3318; 
classtype: attempted-admin; content: “You are mine”; depth: 12; offset:100; content: “AB 8F 23 8A BC 92”; depth:6; 
offset:4;)
   
  The rule above contains 8 syntax or logic errors.  Your task is to review the above rule and identify these errors 
which may prevent the rule from detecting legitimate attacks, or will cause false positives.  For all the mistakes, 
identify the error, explain why it is wrong, and then fix the error.  
  EXAMPLE:
  Here is a sample rule with a mistake in it.
  alert udp any 53 -> any 53 (msg: “DNS attack”; content: “XYZ”;)
   
  Here is an example of the solution format:
   
  Error 1: alert udp any 53 ->
  The source port is given as 53, however requests to a DNS server from a client will use ephemeral ports, and 
therefore should be given as any.  To correct this mistake, the rule should read:
  Solution 1: alert udp any any -> any 53
   
  Make sure to:
  ·         Number each of the errors you find as shown above (ie. Error 1)
  ·         Provide a copy of the portion of the rule which contains the error.  Be sure to include keywords around the 
error to make it clear which part of the rule you are referring to.  If you prefer, for each error, re-write the entire 
rule and highlight the error (see next point)
  ·         Highlight in some way the specific part of the rule you are referring.  In the example above, the source 
port number “53” was underlined.  If you do not make it clear which part of the rule is incorrect, no marks can be 
given.  
  ·         Be sure to include a clear explanation of why the rule was wrong and how it should be fixed
  ·         Re-write the portion of the rule again with the correction included and highlighted (ie underlined)
   
  MARKING CRITERIA:
  Each correctly identified error with a clear explanation and a correct fix for the error will be assigned a ¼ mark.  
No part marks will be assigned, so if you correctly identify the error, but do not provide an appropriate fix or your 
explanation of the error is vague or incorrect, no marks will be assigned.
  (b)                                                                                                                   
(4 marks)  Your supervisor asks you to implement a SNORT IDS rule to detect and alert all attempts at exploiting the 
vulnerability as described below for any computer on the internal network.  He then asks you to write an explanation of 
each component of the rule, so other security specialists in your team can see how your rule is written.  The rule 
should notify the security team when an attempt is made using the message: “NEW PING O’ DEATH EXPLOIT ATTEMPT”.  Be 
sure to allocate an appropriate sid value and a revision number for your new rule, the appropriate class type for this 
attack, and that you include the appropriate CVE id and a nessus vulnerability scanner id as described below. 
   
  A new atomic denial of service attack has been discovered.  It behaves similarly to the Ping o’ death exploit that 
caused great chaos many years ago – once the victim’s computer receives the exploit packet, it will immediately crash.  
Thus, it has been named “New Ping o’ Death” and has a CVE of “2006-0721” and nessus id of “21091”.  The attack is a 
single ping request with an invalid code field.  Current variants of the exploit have been using a code field value of 
‘1001’ (expressed here in binary), however your rule should detect all ping requests with an invalid code field value.  
Furthermore, to exploit the vulnerability the type of service value should be set to “Minimise delay”.  
   
  An example of how to layout your solution follows:
   
  var HOME_NET 138.77.23.0/16
  var EXTERNAL_NET !138.77.23.0/16
  Your explanation of the above in italics
  drop udp $EXTERNAL_NET any -> $HOME_NET 993
  Your explanation of the above, and so on…
   
  An example explanation for a SNORT rule option:
    content: “USER root”; nocase;
  The content of the packet must contain the string “USER root” to be matched.  Furthermore, the nocase option 
specifies that the string “USER root” should be matched case insensitively.  In other words, it will match that string 
whether in upper, lower or mixed capitalisation.
  
  

                
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