Wireshark mailing list archives
Re: help me please
From: Wes <wes_r () yahoo com>
Date: Mon, 19 Apr 2010 07:21:57 -0700 (PDT)
Using the Capture filter "host x.x.x.x" should capture anything From or To the x.x.x.x address.
Wes
--- On Mon, 4/19/10, Miszcsi Miszcsi <miszcsike () yahoo com> wrote:
From: Miszcsi Miszcsi <miszcsike () yahoo com>
Subject: Re: [Wireshark-users] help me please
To: "Community support list for Wireshark" <wireshark-users () wireshark org>
Date: Monday, April 19, 2010, 5:53 AM
Hello Everybody. Thanks Wes for help, it was very usefull, I got the right direction. The problem is that the host
qualifier refers only as source to the IP adress and not as destination too. How can I make a capture filter for
analysing both incoming and outgoing packets for a certain IP adress ? Using "and" and "src host"/"dst host"
combinations can I build the filter ?
Have a nice day
Miszcsi
--- On Sat, 4/17/10, Wes <wes_r () yahoo com> wrote:
From: Wes <wes_r () yahoo com>
Subject: Re: [Wireshark-users] help me please
To: "Community support list for Wireshark" <wireshark-users () wireshark org>
Date: Saturday, April 17, 2010, 1:37 PM
One way to attack this is to verify the sniffer is actually capturing the packets in question by doing a capture
without a capture filter. Then you should be able to build a display filter to see only the packets you want. From
that, you should be able to create a capture filter to capture just those packets.
Wes
--- On Sat, 4/17/10, Pedro Tumusok <pedro.tumusok () gmail com> wrote:
From: Pedro Tumusok <pedro.tumusok () gmail com>
Subject: Re: [Wireshark-users] help me please
To: "Community support list for
Wireshark" <wireshark-users () wireshark org>
Date: Saturday, April 17, 2010, 9:09 AM
Why do you need the to use the HOST address as a qualifier?Would not tcp port 5050 be
enough? The reason is simple, because the internal host ip does not exist on the WAN (Internet) it means that this
address is never in any packets that wireshark captures on the WAN interface. Have you tried to run the sniffer on the
LAN interface?
Pedro
On Sat, Apr 17, 2010 at 12:29 PM, Miszcsi Miszcsi <miszcsike () yahoo com> wrote:
Hi
How to figure out the combination ? For this I should visualize somehow the NAT table, but I dont know how to do this.
Thanks
Miszcsi
PS I still need help in this problem :( Everybody on weekend holiday or sleeping ? :D Still stucked with the project...
--- On Sat, 4/17/10, Jaap Keuter <jaap.keuter () xs4all nl> wrote:
From: Jaap Keuter <jaap.keuter () xs4all nl>
Subject: Re: [Wireshark-users] help me please
To: "Community support list for Wireshark" <wireshark-users () wireshark org>
Date: Saturday, April 17, 2010, 8:28 AM
Hi,
It seems like the NAT function is interfering with your capture filter. Maybe you can figure out what
the exact address/port translation function is by looking at all WAN interface data.
Thanks,Jaap
Send from my iPhone
On 17 apr 2010, at 10:09, Miszcsi Miszcsi <miszcsike () yahoo com> wrote:
Hello!
Please somebody help me with my problem ! I'm new in this and I'm stucked with my project because of this problem and
I cannot going further.
Any
concrete and real help would be appreciated.
I'm trying to monitor network traffic on windows gateway
with Wireshark, specially IM traffic, Yahoo Messenger. I have 2
fastethernet cards in the pc, one for WAN and one for LAN.
If I'm
running the sniffer on an internal pc, i have both incoming and
outgoing packets from and to yahoo server or in case of peertopeer
messaging to and from remote discussion partner.
If I'm running the
sniffer on the gateway using WAN interface for capture, I have only
incoming packets, and no outgoing. For filtering @capture I'm using the
option
"tcp port 5050 and host X.X.X.X" where X.X.X.X is the IP adress of the internal pc.
(Wireshark - Capture Options - and I enter in the Capture Filter field this, after then Start)
I
have one staticly assigned real IP on the WAN, and dhcp assigned
private IP's for internal pcs (192.168.0.X), they are assigned based on
each pc's MAC adress, so they are constant and not interchanging. I'm using source NAT on WAN interface.
What I'm doing wrong or why outgoing packets doesn't appear in Wireshark ?
There is an example in Wireshark User's Guide from where I was inspired :
Example 4.1. A capture filter for telnet that captures
traffic to and from a particular host tcp port 23 and host 10.0.0.5
Please somebody explain what is the solution or the problem what
makes that I see only incoming packets and nothing outgoing.
Best Regards
Miszcsi
___________________________________________________________________________
Sent via: Wireshark-users mailing list <wireshark-users () wireshark org>
Archives: http://www.wireshark.org/lists/wireshark-users
Unsubscribe: https://wireshark.org/mailman/options/wireshark-users
mailto:wireshark-users-request () wireshark org?subject=unsubscribe
-----Inline Attachment Follows-----
___________________________________________________________________________
Sent via: Wireshark-users mailing list <wireshark-users () wireshark org>
Archives: http://www.wireshark.org/lists/wireshark-users
Unsubscribe: https://wireshark.org/mailman/options/wireshark-users
mailto:wireshark-users-request () wireshark org?subject=unsubscribe
___________________________________________________________________________
Sent via: Wireshark-users mailing list <wireshark-users () wireshark org>
Archives: http://www.wireshark.org/lists/wireshark-users
Unsubscribe: https://wireshark.org/mailman/options/wireshark-users
mailto:wireshark-users-request () wireshark org?subject=unsubscribe
--
Best regards / Mvh
Jan Pedro Tumusok
I know you love me
And you want to be Friends
And if you dont
at least you need to pretend
-----Inline Attachment Follows-----
___________________________________________________________________________
Sent via: Wireshark-users mailing list <wireshark-users () wireshark org>
Archives: http://www.wireshark.org/lists/wireshark-users
Unsubscribe: https://wireshark.org/mailman/options/wireshark-users
mailto:wireshark-users-request () wireshark org?subject=unsubscribe
-----Inline Attachment Follows-----
___________________________________________________________________________
Sent via: Wireshark-users mailing list <wireshark-users () wireshark org>
Archives: http://www.wireshark.org/lists/wireshark-users
Unsubscribe: https://wireshark.org/mailman/options/wireshark-users
mailto:wireshark-users-request () wireshark org?subject=unsubscribe
-----Inline Attachment Follows-----
___________________________________________________________________________
Sent via: Wireshark-users mailing list <wireshark-users () wireshark org>
Archives: http://www.wireshark.org/lists/wireshark-users
Unsubscribe: https://wireshark.org/mailman/options/wireshark-users
mailto:wireshark-users-request () wireshark org?subject=unsubscribe
___________________________________________________________________________ Sent via: Wireshark-users mailing list <wireshark-users () wireshark org> Archives: http://www.wireshark.org/lists/wireshark-users Unsubscribe: https://wireshark.org/mailman/options/wireshark-users mailto:wireshark-users-request () wireshark org?subject=unsubscribe
Current thread:
- help me please Miszcsi Miszcsi (Apr 17)
- Re: help me please Jaap Keuter (Apr 17)
- Re: help me please Miszcsi Miszcsi (Apr 17)
- Re: help me please Pedro Tumusok (Apr 17)
- Re: help me please Miszcsi Miszcsi (Apr 17)
- Re: help me please Wes (Apr 17)
- Re: help me please Miszcsi Miszcsi (Apr 19)
- Re: help me please Wes (Apr 19)
- Re: help me please Forthofer Russ (Apr 19)
- Re: help me please dan meyer (Apr 19)
- Re: help me please Miszcsi Miszcsi (Apr 19)
- Re: help me please Miszcsi Miszcsi (Apr 17)
- Re: help me please Jaap Keuter (Apr 17)
