Wireshark mailing list archives
bitwise operating gives syntax error. + displaying a slice.
From: Marilo <narium85-mlscar () yahoo co uk>
Date: Sun, 8 Apr 2012 16:37:38 +0100 (BST)
I am having trouble trying to get the bitwise operator to function here without a syntax error
This works
C:\sdf>tshark -r asdf2 "ip[0]==45"
but when I put a bitwise AND in there, I get a syntax error
C:\sdf>tshark -r asdf2 "ip[0]&0==45"
tshark: Syntax error.
Note: That display filter code looks like a valid capture filter;
maybe you mixed them up?
C:\sdf>
Also where in the manual does it speak about this?
And it'd be really useful in debugging a filter, if I could display, say, ip[0] or ip[0]<<2
Is that possible and is it possible to only display ip[0] or tcp[12] or whatever slice, of a packet?
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Current thread:
- bitwise operating gives syntax error. + displaying a slice. Marilo (Apr 08)
- Re: bitwise operating gives syntax error. + displaying a slice. Jaap Keuter (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Marilo (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Sam Roberts (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Marilo (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Sake Blok (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Jaap Keuter (Apr 09)
