Wireshark mailing list archives
Re: Enabling protocol in Decode As dialog
From: Guy Harris <guy () alum mit edu>
Date: Fri, 10 Jun 2016 10:57:24 -0700
On Jun 10, 2016, at 10:40 AM, Robert Cragie <robert.cragie () gridmerge com> wrote:
It's more like a tunnelling protocol e.g. L2TP where L2 runs atop a L4 protocol - which is not "conventional".
"Conventional" is irrelevant to Wireshark - from the standpoint of Wireshark, X runs atop Y if:
Y has a mechanism for handing its payload to other dissectors;
X's dissector is one of the ones to which it can hand its payload;
regardless of where X and Y "normally" happen to live in the protocol stack.
So, if protocol Y has a dissector table and thus also has support for "decode as", registering X's dissector with Y is
done the same way regardless of whether the layering is "conventional" or not; "unconventional" must not affect how you
think of setting up your dissector - or how you ask about how to set up your dissector.
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Current thread:
- Enabling protocol in Decode As dialog Robert Cragie (Jun 08)
- Re: Enabling protocol in Decode As dialog Guy Harris (Jun 08)
- Re: Enabling protocol in Decode As dialog Robert Cragie (Jun 08)
- Re: Enabling protocol in Decode As dialog Guy Harris (Jun 09)
- Re: Enabling protocol in Decode As dialog Robert Cragie (Jun 10)
- Re: Enabling protocol in Decode As dialog Guy Harris (Jun 10)
- Re: Enabling protocol in Decode As dialog Robert Cragie (Jun 10)
- Re: Enabling protocol in Decode As dialog Guy Harris (Jun 10)
- Re: Enabling protocol in Decode As dialog Robert Cragie (Jun 12)
- Re: Enabling protocol in Decode As dialog Robert Cragie (Jun 08)
- Re: Enabling protocol in Decode As dialog Guy Harris (Jun 08)
